您现在的位置是:网站首页> 编程资料编程资料
python绘制玫瑰花情人节表白_python_
2023-05-26
338人已围观
简介 python绘制玫瑰花情人节表白_python_
一、玫瑰花绘制—深红色

import numpy as np import matplotlib.pyplot as plt from mpl_toolkits.mplot3d import Axes3D fig = plt.figure() ax = fig.gca(projection='3d') [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 30 * np.pi - 4*np.pi) p = (np.pi / 2) * np.exp(-t / (8 * np.pi)) change = np.sin(20*t)/50 u = 1 - (1 - np.mod(3.3 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change y = 2 * (x ** 2 - x) ** 2 * np.sin(p) r = u * (x * np.sin(p) + y * np.cos(p)) * 1.5 h = u * (x * np.cos(p) - y * np.sin(p)) c= plt.get_cmap('magma') surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1, cmap= c, linewidth=0, antialiased=True) plt.show()二、玫瑰花绘制—五颜六色


import numpy as np import matplotlib.pyplot as plt from matplotlib import cm from mpl_toolkits.mplot3d import Axes3D fig = plt.figure() ax = fig.gca(projection='3d') [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 17 * np.pi - 2 * np.pi) p = (np.pi / 2) * np.exp(-t / (8 * np.pi)) u = 1 - (1 - np.mod(3.6 * t, 2 * np.pi) / np.pi) ** 4 / 2 y = 2 * (x ** 2 - x) ** 2 * np.sin(p) r = u * (x * np.sin(p) + y * np.cos(p)) h = u * (x * np.cos(p) - y * np.sin(p)) c= cm.gist_rainbow_r surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1, cmap= c, linewidth=0, antialiased=True) plt.show()
三、玫瑰花绘制—粉红色

import numpy as np import matplotlib.pyplot as plt from matplotlib import cm from mpl_toolkits.mplot3d import Axes3D fig = plt.figure() ax = fig.gca(projection='3d') [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 17 * np.pi - 2 * np.pi) p = (np.pi / 2) * np.exp(-t / (8 * np.pi)) u = 1 - (1 - np.mod(3.6 * t, 2 * np.pi) / np.pi) ** 4 / 2 y = 2 * (x ** 2 - x) ** 2 * np.sin(p) r = u * (x * np.sin(p) + y * np.cos(p)) h = u * (x * np.cos(p) - y * np.sin(p)) c= cm.get_cmap('spring_r') surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1, cmap= c, linewidth=0, antialiased=True) plt.show()四、玫瑰花绘制—红色

# 省略了头文件,可以在之前的博客里看到 import numpy as np import matplotlib.pyplot as plt from mpl_toolkits.mplot3d import Axes3D fig = plt.figure() ax = fig.gca(projection='3d') # 将相位向后移动了6*pi [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 20 * np.pi + 4*np.pi) p = (np.pi / 2) * np.exp(-t / (8 * np.pi)) # 添加边缘扰动 change = np.sin(15*t)/150 # 将t的参数减少,使花瓣的角度变大 u = 1 - (1 - np.mod(3.3 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change y = 2 * (x ** 2 - x) ** 2 * np.sin(p) r = u * (x * np.sin(p) + y * np.cos(p)) h = u * (x * np.cos(p) - y * np.sin(p)) c= plt.get_cmap('Reds') surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1, cmap= c, linewidth=0, antialiased=True) plt.show()五、桃花绘制

import numpy as np import matplotlib.pyplot as plt from mpl_toolkits.mplot3d import Axes3D fig = plt.figure() ax = fig.gca(projection='3d') [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 6 * np.pi - 4*np.pi) p = (np.pi / 2) * np.exp(-t / (8 * np.pi)) change = np.sin(10*t)/20 u = 1 - (1 - np.mod(5.2 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change y = 2 * (x ** 2 - x) ** 2 * np.sin(p) r = u * (x * np.sin(p) + y * np.cos(p)) * 1.5 h = u * (x * np.cos(p) - y * np.sin(p)) c= plt.get_cmap('spring_r') surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1, cmap= c, linewidth=0, antialiased=True) plt.show()到此这篇关于python绘制玫瑰花情人节表白的文章就介绍到这了,更多相关python绘制玫瑰花内容请搜索以前的文章或继续浏览下面的相关文章希望大家以后多多支持!
您可能感兴趣的文章:
相关内容
- Python 常见的配置文件写法梳理汇总_python_
- Python解析器Cpython的GIL解释器锁工作机制_python_
- 基于Python实现GeoServer矢量文件批量发布_python_
- python多线程对多核cpu的利用解析_python_
- python实现GATK多线程加速示例_python_
- Python+Selenium实现在Geoserver批量发布Mongo矢量数据_python_
- 使用matplotlib绘制并排柱状图的实战案例_python_
- python PyVCF文件处理VCF文件格式实例详解_python_
- Selenium多窗口切换解决方案_python_
- 如何用Python 实现景区安防系统_python_
